One of the interesting data reports is the following:
Top 50 Quality Users
(based on post score calculated using reply count, likes, incoming links, bookmarks, time spent and read count)
So who are our âhighest qualityâ users?
One of the interesting data reports is the following:
Top 50 Quality Users
(based on post score calculated using reply count, likes, incoming links, bookmarks, time spent and read count)
So who are our âhighest qualityâ users?
@Robert.A.Jr is not going to be happy one bit not seeing his name on here.
What does Post Count refer to in this report? Itâs not their actual total post count.
the interval is 6 months
Whereâs the metric for PWI?
Interesting.
Not exactly sure how those parameters count? But it sounds like i could get a top spot for writing long provocative posts about Burgundy in every single Burgundy thread?
(well most threads seem to turn into a Burgundy thread).
Wish I had the time available in the day to be be on that list and spend that much of my day thinking about wine!
How do you think I feel??
Iâm proud to be a low-grade, middling, mediocre poster.
Results obviously reflect a bias⊠the count was âstolenââŠ
No idea what this means, but either humiliated or honored to be included.
So being a perpetual lurker doesnât get me there. Fair enough.
How unexpected. Thank you Todd
thereâs a list for that, as well! âMost Active LurkersââŠbut you arenât on that, either (however, three other Jens on that list). I can find a list you are part of, trophies abound!
Hmm, and here I thought that was from a non-PC rap song!
I demand a recount!!! Toddâs dominion and control has been hacked from Venezuela!
Remember I shared the code with you, feel free to utilize it to generate the results you want! You have so many badges, Chris should be very proud of your success here!
SELECT sum(p.score) / count(p) AS âaverage score per postâ,
count(p.id) AS post_count,
p.user_id
FROM posts p
JOIN users u ON u.id = p.user_id
WHERE p.created_at >= CURRENT_DATE - INTERVAL â6 monthâ
AND NOT u.admin
AND u.active
GROUP BY user_id,
u.views
HAVING count(p.id) > 50
ORDER BY sum(p.score) / count(p) DESC
LIMIT 50
Wait, Iâm on this list? Someone more âhigh qualityâ than me said something about refusing to join any club that would have me as a memberâŠ
I canât deny the fact that you like me. Right now, you like me.
Darn you stole my joke!
But I was going to use it to emphasize that Iâm glad Iâm not on the list!